Experiment 8-4824

	Rb	Vbe	Vce	Ib	Ic
R1	4.7K	0.77	0.03	0.9ma	6.7ma
R2	22K	0.74	0.06	0.2ma	6.5ma
R3	27K	0.73	0.07	164µ	6.45ma
R4	330K	0.68	1.49	14µ	3.67ma
R5	1M	0.65	2.7	5µ	1.24ma

The Vce increased as the resistance increased. This caused the transistor to go from saturation to active, as there was less current to use.

There was close to no change at Vbe as the transistor always needs 0.7-0.8 to operate.

Ib decreased as the resistance increased. There became less current for the transistor to work with.

Ic also decreased as the resistance increased. This provided less current to be amplified.

My Graph of the results.

Using this formula; B=Ic/Ib I found the Beta at each Vce.

The Beta of this transistor at:

1. Vce of 0.03 6.7ma / 0.9ma B= 7
   
2. Vce of 0.06 6.5ma / 0.2ma B=32
3. Vce of 0.07 6.45ma / 0.164ma B=39
4. Vce of 1.49 3.67ma / 0.014ma B=262
5. Vce of 2.7 1.24ma / 0.005ma B=248
   

The graph can show us the areas of the activeness of the transistor. At the highest Vce the transistor is in the cut off area as it is almost off. At 1.5 Vce the transistor is active, but is still not fully active. The three Vce readings under 0.2 show that the transistor is saturated and is now fully active.